Calculus Find dy/dx y = square root of 2x1 y = √2x 1 y = 2 x 1 Use n√ax = ax n a x n = a x n to rewrite √2x1 2 x 1 as (2x1)1 2 ( 2 x 1) 1 2 y = (2x 1)1 2 y = ( 2 x 1) 1 2 Differentiate
Y=sin^-1(2x/1+x^2) find dy/dx-Y(0)=1Also visit my website https//wwwtheissbcom/math for learning other stufFind dxdy if y = sin −1(14 x2 x1) Medium Solution Verified by Toppr Given y=sin −1(14 x2 x1)=sin −1(1(2 x) 22×2 x) Let 2 x=tanθ θ=tan −1(2 x) So y=sin −1(1tan 2θ2tanθ)=sin
Y=sin^-1(2x/1+x^2) find dy/dxのギャラリー
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